The kinematics of 3D duration (3D time) have been explored here over the past year. Now let’s look at the dynamics of 3D duration. This will be done in 1D in order to allow generalizations to 3D length or 3D duration. Start with momentum, the mass times velocity: p = mv. According to Newton’s second law, force is the time rate of change of momentum:
F = Δp/Δt = m Δv/Δt = ma,
with acceleration a. Multiplying by Δt gives the impulse, J:
J = F Δt = Δp = m Δv.
The reciprocal of this equation leads to
1/J = 1/(F Δt) = 1/Δp = (1/m) (1/Δv).
For 1D the 1/Δv equals Δℓ, the change in lenticity. Let q = ℓ/m, which could be called the levamentum on analogy with the momentum. Then
1/Δp = (1/m) (1/Δv) = (1/m) Δℓ = Δq.
Divide through by Δr to get
Δq/Δr = (1/m) Δℓ/Δr = b/m
where b is the relentation. This is like force, with smaller values indicating greater dynamics – call it release, symbolized by M:
M = b/m.
Since this form of Newton’s second law is a function of relentation instead of acceleration, it can be generalized to three time dimensions.