Lorentz-like transformations for time-distance domain
What follows are derivations of the Lorentz transformation for the time domain and a Lorentz-like transformation for the distance domain.
Time Domain
Consider two inertial frames of reference O and O′, assuming O to be at rest while O′ is moving with velocity v with respect to O in the positive x-direction. The origins of O and O′ initially coincide with each other. A light signal is emitted from the common origin and travels as a spherical wave front. Consider a point P on a spherical wavefront at a length rx and rx′ from the origins of O and O′ respectively.
For round-trip motion, the mean round-trip speed of light, c, is the same in all inertial frames, so for the point P with length vector r = (rx,0, 0) and
rx = ct, and rx′ = ct′.
Consider the standard Galilean transformation with a factor γ, which is to be determined and may depend on β, where β = v/c:
rx′ = γ(rx − vt) = γ(rx − βct) = γ(rx − βct) = γrx(1 − β).
The inverse transformation is the same except that the sign of β is reversed:
rx = γ(rx′ + vt′) = γ(rx′ + βct′)= γ(rx′ + βct′) = γrx′(1 + β).
Multiply these two equations together to get
rxrx′ = γ² rxrx′(1 − β²).
Divide out rxrx′ to get
γ² = 1/(1 − β²),
or γ = 1/√(1 − β²).
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Consider what happens if this approach is applied to the independent time t times the constant c.
ct′ = rx′ = γ(ct − βrx) = γ(rx − βrx) = γrx(1 − β).
The inverse transformation is the same except that the sign of β is reversed:
ct = rx = γ(ct′ + βrx′) = γ(rx′ + βrx′) = γrx′(1 + β).
These are exactly the same equations as before, so the result will be the same.
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Distance Domain
Consider two inertial frames of reference O and O′, assuming O to be at rest while O′ is moving with rapidity p with respect to O in the positive x-direction. The origins of O and O′ initially coincide with each other. A light signal is emitted from the common origin and travels as a spherical wave front. Consider a point Q on a spherical wavefront at a duration ux and ux′ from the origins of O and O′ respectively.
For round-trip motion, the mean round-trip pace of light, k, is the same in all inertial frames, so for the point Q with duration vector u = (ux,0, 0) and
ux = ks, and ux′ = ks′.
Consider the dual standard Galilean transformation with a factor λ, which is to be determined and may depend on α = p/k (cf. c/v)
ux′ = λ(ux − ps) = λ(ux − αks) = λ(ux − αux) = λux(1 − α).
The inverse transformation is the same except that the sign of β is reversed:
ux = λ(ux′ + ps′) = λ(ux′ + αks′) = λ(ux′ + αux′) = λux′(1 + α).
Multiply these two equations to get
uxux′ = λ2uxux′(1 − α²).
Divide out uxux′ to get
λ² = 1/(1 − α²), or
λ = 1/√(1 − α²).
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Consider what happens if this approach is applied to the independent distance s times the constant k.
ks′ = ux′ = λ(ks − αux) = λ(ux − αux) = λux(1 − α).
The inverse transformation is the same except that the sign of α is reversed:
ks = ux = λ(ks′ + αux′) = λ(ux′ + αux′) = λux′(1 + α).
These are exactly the same equations as before, so the result will be the same.
RG 2026-04-04
